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1140004220433 = 31384193472013
BaseRepresentation
bin10000100101101101100…
…010111110111000010001
311000222112212001201120120
4100211231202332320101
5122134212040023213
62231413302500453
7145235236663551
oct20455542767021
94028485051516
101140004220433
113aa5227319a1
12164b35134729
138366a9a7820
143d268453161
151e9c2a1d423
hex1096d8bee11

1140004220433 has 16 divisors (see below), whose sum is σ = 1637124041280. Its totient is φ = 701457528384.

The previous prime is 1140004220431. The next prime is 1140004220477. The reversal of 1140004220433 is 3340224000411.

It is not a de Polignac number, because 1140004220433 - 21 = 1140004220431 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1140004220431) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1407666 + ... + 2064347.

It is an arithmetic number, because the mean of its divisors is an integer number (102320252580).

Almost surely, 21140004220433 is an apocalyptic number.

1140004220433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1140004220433 is a deficient number, since it is larger than the sum of its proper divisors (497119820847).

1140004220433 is a wasteful number, since it uses less digits than its factorization.

1140004220433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3480448.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 1140004220433 its reverse (3340224000411), we get a palindrome (4480228220844).

The spelling of 1140004220433 in words is "one trillion, one hundred forty billion, four million, two hundred twenty thousand, four hundred thirty-three".

Divisors: 1 3 13 39 8419 25257 109447 328341 3472013 10416039 45136169 135408507 29230877447 87692632341 380001406811 1140004220433