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1140011213241 = 3380003737747
BaseRepresentation
bin10000100101101101111…
…101101010000110111001
311000222120100012222220110
4100211231331222012321
5122134220332310431
62231414112414533
7145235353300005
oct20455575520671
94028510188813
101140011213241
113aa52667877a
12164b37547449
138366c285694
143d269353705
151e9c3450346
hex1096df6a1b9

1140011213241 has 4 divisors (see below), whose sum is σ = 1520014950992. Its totient is φ = 760007475492.

The previous prime is 1140011213221. The next prime is 1140011213267. The reversal of 1140011213241 is 1423121100411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1140011213241 - 217 = 1140011082169 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1140011213221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190001868871 + ... + 190001868876.

It is an arithmetic number, because the mean of its divisors is an integer number (380003737748).

Almost surely, 21140011213241 is an apocalyptic number.

It is an amenable number.

1140011213241 is a deficient number, since it is larger than the sum of its proper divisors (380003737751).

1140011213241 is an equidigital number, since it uses as much as digits as its factorization.

1140011213241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 380003737750.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 1140011213241 its reverse (1423121100411), we get a palindrome (2563132313652).

The spelling of 1140011213241 in words is "one trillion, one hundred forty billion, eleven million, two hundred thirteen thousand, two hundred forty-one".

Divisors: 1 3 380003737747 1140011213241