Base | Representation |
---|---|
bin | 110101000101100000… |
… | …0011111101010111001 |
3 | 101220020221120201011011 |
4 | 1222023000133222321 |
5 | 3331433313444231 |
6 | 124212123433521 |
7 | 11144026111252 |
oct | 1521300375271 |
9 | 356227521134 |
10 | 114001312441 |
11 | 443908503a5 |
12 | 1a1169858a1 |
13 | a99a48aac3 |
14 | 5736799b29 |
15 | 2e7352b9b1 |
hex | 1a8b01fab9 |
114001312441 has 2 divisors, whose sum is σ = 114001312442. Its totient is φ = 114001312440.
The previous prime is 114001312379. The next prime is 114001312457. The reversal of 114001312441 is 144213100411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 59525752441 + 54475560000 = 243979^2 + 233400^2 .
It is a cyclic number.
It is not a de Polignac number, because 114001312441 - 227 = 113867094713 is a prime.
It is not a weakly prime, because it can be changed into another prime (114001318441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57000656220 + 57000656221.
It is an arithmetic number, because the mean of its divisors is an integer number (57000656221).
Almost surely, 2114001312441 is an apocalyptic number.
It is an amenable number.
114001312441 is a deficient number, since it is larger than the sum of its proper divisors (1).
114001312441 is an equidigital number, since it uses as much as digits as its factorization.
114001312441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 114001312441 its reverse (144213100411), we get a palindrome (258214412852).
The spelling of 114001312441 in words is "one hundred fourteen billion, one million, three hundred twelve thousand, four hundred forty-one".
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