Base | Representation |
---|---|
bin | 11001111010111100110110… |
… | …100110101010100111010011 |
3 | 112221122111200122002211201202 |
4 | 121322330312212222213103 |
5 | 104420303033124342121 |
6 | 1042243523003421415 |
7 | 33004250416214426 |
oct | 3172746646524723 |
9 | 487574618084652 |
10 | 114002233043411 |
11 | 33363091580389 |
12 | 1095249122486b |
13 | 4b7c4978ca84b |
14 | 2021a47a7d9bd |
15 | d2a6d676540b |
hex | 67af369aa9d3 |
114002233043411 has 2 divisors, whose sum is σ = 114002233043412. Its totient is φ = 114002233043410.
The previous prime is 114002233043399. The next prime is 114002233043417. The reversal of 114002233043411 is 114340332200411.
It is a strong prime.
It is an emirp because it is prime and its reverse (114340332200411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114002233043411 - 214 = 114002233027027 is a prime.
It is not a weakly prime, because it can be changed into another prime (114002233043417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57001116521705 + 57001116521706.
It is an arithmetic number, because the mean of its divisors is an integer number (57001116521706).
Almost surely, 2114002233043411 is an apocalyptic number.
114002233043411 is a deficient number, since it is larger than the sum of its proper divisors (1).
114002233043411 is an equidigital number, since it uses as much as digits as its factorization.
114002233043411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 114002233043411 its reverse (114340332200411), we get a palindrome (228342565243822).
The spelling of 114002233043411 in words is "one hundred fourteen trillion, two billion, two hundred thirty-three million, forty-three thousand, four hundred eleven".
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