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11400233321234 = 25700116660617
BaseRepresentation
bin1010010111100101001011…
…0110111000001100010010
31111100211222212020222212102
42211321102312320030102
52443240134212234414
640125110032400402
72254432260242222
oct245712266701422
944324885228772
1011400233321234
1136a58a2562a7a
1213415370a6102
136490641b52a4
142b5aba712082
1514b82d7deede
hexa5e52db8312

11400233321234 has 4 divisors (see below), whose sum is σ = 17100349981854. Its totient is φ = 5700116660616.

The previous prime is 11400233321189. The next prime is 11400233321249. The reversal of 11400233321234 is 43212333200411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10837362760225 + 562870561009 = 3292015^2 + 750247^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11400233321197 and 11400233321206.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2850058330307 + ... + 2850058330310.

Almost surely, 211400233321234 is an apocalyptic number.

11400233321234 is a deficient number, since it is larger than the sum of its proper divisors (5700116660620).

11400233321234 is an equidigital number, since it uses as much as digits as its factorization.

11400233321234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5700116660619.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 11400233321234 its reverse (43212333200411), we get a palindrome (54612566521645).

The spelling of 11400233321234 in words is "eleven trillion, four hundred billion, two hundred thirty-three million, three hundred twenty-one thousand, two hundred thirty-four".

Divisors: 1 2 5700116660617 11400233321234