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11400234012403 = 53732946558287
BaseRepresentation
bin1010010111100101001011…
…1001100000111011110011
31111100211222220120002222021
42211321102321200323303
52443240134401344103
640125110055252311
72254432266151255
oct245712271407363
944324886502867
1011400234012403
1136a58a2995295
12134153737a097
13649064397a72
142b5aba851cd5
1514b82d8c9bbd
hexa5e52e60ef3

11400234012403 has 8 divisors (see below), whose sum is σ = 11774446918848. Its totient is φ = 11031914222784.

The previous prime is 11400234012397. The next prime is 11400234012407. The reversal of 11400234012403 is 30421043200411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11400234012403 - 25 = 11400234012371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11400234012407) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1473275275 + ... + 1473283012.

It is an arithmetic number, because the mean of its divisors is an integer number (1471805864856).

Almost surely, 211400234012403 is an apocalyptic number.

11400234012403 is a deficient number, since it is larger than the sum of its proper divisors (374212906445).

11400234012403 is an equidigital number, since it uses as much as digits as its factorization.

11400234012403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2946558413.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 11400234012403 its reverse (30421043200411), we get a palindrome (41821277212814).

The spelling of 11400234012403 in words is "eleven trillion, four hundred billion, two hundred thirty-four million, twelve thousand, four hundred three".

Divisors: 1 53 73 3869 2946558287 156167589211 215098754951 11400234012403