Base | Representation |
---|---|
bin | 1010010111100101011110… |
… | …1011000101000010000001 |
3 | 1111100212012111021200221122 |
4 | 2211321113223011002001 |
5 | 2443240320403123202 |
6 | 40125122040202025 |
7 | 2254434261050162 |
oct | 245712753050201 |
9 | 44325174250848 |
10 | 11400314114177 |
11 | 36a59341259aa |
12 | 134155a169315 |
13 | 649077b62571 |
14 | 2b5ac7343769 |
15 | 14b83594d9a2 |
hex | a5e57ac5081 |
11400314114177 has 2 divisors, whose sum is σ = 11400314114178. Its totient is φ = 11400314114176.
The previous prime is 11400314114089. The next prime is 11400314114291. The reversal of 11400314114177 is 77141141300411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8085696983296 + 3314617130881 = 2843536^2 + 1820609^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11400314114177 is a prime.
It is not a weakly prime, because it can be changed into another prime (11400314119177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700157057088 + 5700157057089.
It is an arithmetic number, because the mean of its divisors is an integer number (5700157057089).
Almost surely, 211400314114177 is an apocalyptic number.
It is an amenable number.
11400314114177 is a deficient number, since it is larger than the sum of its proper divisors (1).
11400314114177 is an equidigital number, since it uses as much as digits as its factorization.
11400314114177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9408, while the sum is 35.
Adding to 11400314114177 its reverse (77141141300411), we get a palindrome (88541455414588).
The spelling of 11400314114177 in words is "eleven trillion, four hundred billion, three hundred fourteen million, one hundred fourteen thousand, one hundred seventy-seven".
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