Base | Representation |
---|---|
bin | 10101001111000010… |
… | …00100110010110011 |
3 | 1002102111212022211221 |
4 | 22213201010302303 |
5 | 141322000300201 |
6 | 5123130045511 |
7 | 552340541635 |
oct | 124741046263 |
9 | 32374768757 |
10 | 11400400051 |
11 | 4920257327 |
12 | 2261b79897 |
13 | 10c8b79061 |
14 | 7a213aa55 |
15 | 46acd14a1 |
hex | 2a7844cb3 |
11400400051 has 4 divisors (see below), whose sum is σ = 11432156400. Its totient is φ = 11368643704.
The previous prime is 11400400013. The next prime is 11400400057. The reversal of 11400400051 is 15000400411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11400400051 - 219 = 11399875763 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11400399998 and 11400400034.
It is not an unprimeable number, because it can be changed into a prime (11400400057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15877636 + ... + 15878353.
It is an arithmetic number, because the mean of its divisors is an integer number (2858039100).
Almost surely, 211400400051 is an apocalyptic number.
11400400051 is a deficient number, since it is larger than the sum of its proper divisors (31756349).
11400400051 is an equidigital number, since it uses as much as digits as its factorization.
11400400051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31756348.
The product of its (nonzero) digits is 80, while the sum is 16.
Adding to 11400400051 its reverse (15000400411), we get a palindrome (26400800462).
The spelling of 11400400051 in words is "eleven billion, four hundred million, four hundred thousand, fifty-one".
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