Base | Representation |
---|---|
bin | 11001111010111110100001… |
… | …110010001010110110111001 |
3 | 112221122200022221200201220021 |
4 | 121322332201302022312321 |
5 | 104420320223443034202 |
6 | 1042244421240530441 |
7 | 33004343112402256 |
oct | 3172764162126671 |
9 | 487580287621807 |
10 | 114004031221177 |
11 | 333639245aaa09 |
12 | 109528b3480a21 |
13 | 4b7c6c3300366 |
14 | 2021b7880042d |
15 | d2a78e55da37 |
hex | 67afa1c8adb9 |
114004031221177 has 2 divisors, whose sum is σ = 114004031221178. Its totient is φ = 114004031221176.
The previous prime is 114004031221103. The next prime is 114004031221193. The reversal of 114004031221177 is 771122130400411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76153617372816 + 37850413848361 = 8726604^2 + 6152269^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114004031221177 is a prime.
It is not a weakly prime, because it can be changed into another prime (114004031222177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57002015610588 + 57002015610589.
It is an arithmetic number, because the mean of its divisors is an integer number (57002015610589).
Almost surely, 2114004031221177 is an apocalyptic number.
It is an amenable number.
114004031221177 is a deficient number, since it is larger than the sum of its proper divisors (1).
114004031221177 is an equidigital number, since it uses as much as digits as its factorization.
114004031221177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9408, while the sum is 34.
Adding to 114004031221177 its reverse (771122130400411), we get a palindrome (885126161621588).
The spelling of 114004031221177 in words is "one hundred fourteen trillion, four billion, thirty-one million, two hundred twenty-one thousand, one hundred seventy-seven".
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