Base | Representation |
---|---|
bin | 10101001111000111… |
… | …01111110001110010 |
3 | 1002102120011220112212 |
4 | 22213203233301302 |
5 | 141322140203102 |
6 | 5123153052122 |
7 | 552346516526 |
oct | 124743576162 |
9 | 32376156485 |
10 | 11401100402 |
11 | 492069552a |
12 | 2262257042 |
13 | 10c9062a73 |
14 | 7a227dd86 |
15 | 46adbdc52 |
hex | 2a78efc72 |
11401100402 has 4 divisors (see below), whose sum is σ = 17101650606. Its totient is φ = 5700550200.
The previous prime is 11401100383. The next prime is 11401100429. The reversal of 11401100402 is 20400110411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 6937390681 + 4463709721 = 83291^2 + 66811^2 .
It is a super-3 number, since 3×114011004023 (a number of 31 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2850275099 + ... + 2850275102.
Almost surely, 211401100402 is an apocalyptic number.
11401100402 is a deficient number, since it is larger than the sum of its proper divisors (5700550204).
11401100402 is an equidigital number, since it uses as much as digits as its factorization.
11401100402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5700550203.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 11401100402 its reverse (20400110411), we get a palindrome (31801210813).
The spelling of 11401100402 in words is "eleven billion, four hundred one million, one hundred thousand, four hundred two".
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