Base | Representation |
---|---|
bin | 10000100101110011111… |
… | …011000101111100100011 |
3 | 11000222211022101001121202 |
4 | 100211303323011330203 |
5 | 122134421432013011 |
6 | 2231432043511415 |
7 | 145241006223434 |
oct | 20456373057443 |
9 | 4028738331552 |
10 | 1140111204131 |
11 | 3aa578063379 |
12 | 164b64b2856b |
13 | 83686bc4ca3 |
14 | 3d27874148b |
15 | 1e9cc10223b |
hex | 10973ec5f23 |
1140111204131 has 4 divisors (see below), whose sum is σ = 1200117057000. Its totient is φ = 1080105351264.
The previous prime is 1140111204121. The next prime is 1140111204139. The reversal of 1140111204131 is 1314021110411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1140111204131 - 218 = 1140110941987 is a prime.
It is a super-2 number, since 2×11401112041312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1140111204139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30002926406 + ... + 30002926443.
It is an arithmetic number, because the mean of its divisors is an integer number (300029264250).
Almost surely, 21140111204131 is an apocalyptic number.
1140111204131 is a deficient number, since it is larger than the sum of its proper divisors (60005852869).
1140111204131 is an equidigital number, since it uses as much as digits as its factorization.
1140111204131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60005852868.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 1140111204131 its reverse (1314021110411), we get a palindrome (2454132314542).
The spelling of 1140111204131 in words is "one trillion, one hundred forty billion, one hundred eleven million, two hundred four thousand, one hundred thirty-one".
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