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114011312132 = 2228502828033
BaseRepresentation
bin110101000101110011…
…0101001000000000100
3101220021122101202011002
41222023212221000010
53331443343442012
6124213122032432
711144210110004
oct1521346510004
9356248352132
10114011312132
1144396460303
121a11a1a8718
13a99c57c493
145737c40004
152e743547c2
hex1a8b9a9004

114011312132 has 6 divisors (see below), whose sum is σ = 199519796238. Its totient is φ = 57005656064.

The previous prime is 114011312111. The next prime is 114011312137. The reversal of 114011312132 is 231213110411.

114011312132 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 113964307396 + 47004736 = 337586^2 + 6856^2 .

It is not an unprimeable number, because it can be changed into a prime (114011312137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14251414013 + ... + 14251414020.

It is an arithmetic number, because the mean of its divisors is an integer number (33253299373).

Almost surely, 2114011312132 is an apocalyptic number.

It is an amenable number.

114011312132 is a deficient number, since it is larger than the sum of its proper divisors (85508484106).

114011312132 is a wasteful number, since it uses less digits than its factorization.

114011312132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28502828037 (or 28502828035 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 114011312132 its reverse (231213110411), we get a palindrome (345224422543).

The spelling of 114011312132 in words is "one hundred fourteen billion, eleven million, three hundred twelve thousand, one hundred thirty-two".

Divisors: 1 2 4 28502828033 57005656066 114011312132