Base | Representation |
---|---|
bin | 11001111011000101011010… |
… | …110110111001110101100011 |
3 | 112221200101102200002100021122 |
4 | 121323011122312321311203 |
5 | 104420430402342330220 |
6 | 1042252043424242455 |
7 | 33005024356324526 |
oct | 3173053266716543 |
9 | 487611380070248 |
10 | 114011431214435 |
11 | 33366a81715417 |
12 | 1095421977042b |
13 | 4b803024447b1 |
14 | 202227b51cbbd |
15 | d2aa74039425 |
hex | 67b15adb9d63 |
114011431214435 has 16 divisors (see below), whose sum is σ = 145987239977760. Its totient is φ = 85224983328000.
The previous prime is 114011431214431. The next prime is 114011431214437. The reversal of 114011431214435 is 534412134110411.
It is not a de Polignac number, because 114011431214435 - 22 = 114011431214431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114011431214395 and 114011431214404.
It is not an unprimeable number, because it can be changed into a prime (114011431214431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8219995316 + ... + 8220009185.
It is an arithmetic number, because the mean of its divisors is an integer number (9124202498610).
Almost surely, 2114011431214435 is an apocalyptic number.
114011431214435 is a deficient number, since it is larger than the sum of its proper divisors (31975808763325).
114011431214435 is a wasteful number, since it uses less digits than its factorization.
114011431214435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16440004598.
The product of its (nonzero) digits is 23040, while the sum is 35.
Adding to 114011431214435 its reverse (534412134110411), we get a palindrome (648423565324846).
The spelling of 114011431214435 in words is "one hundred fourteen trillion, eleven billion, four hundred thirty-one million, two hundred fourteen thousand, four hundred thirty-five".
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