Base | Representation |
---|---|
bin | 11001111011000101011111… |
… | …100011100001100001001011 |
3 | 112221200101122011101002102121 |
4 | 121323011133203201201023 |
5 | 104420431033031121141 |
6 | 1042252055321312111 |
7 | 33005026334215051 |
oct | 3173053743414113 |
9 | 487611564332377 |
10 | 114011510020171 |
11 | 33367012150325 |
12 | 10954240035637 |
13 | 4b803158773ca |
14 | 2022287b941d1 |
15 | d2aa7ae041d1 |
hex | 67b15f8e184b |
114011510020171 has 2 divisors, whose sum is σ = 114011510020172. Its totient is φ = 114011510020170.
The previous prime is 114011510020129. The next prime is 114011510020223. The reversal of 114011510020171 is 171020015110411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114011510020171 - 217 = 114011509889099 is a prime.
It is not a weakly prime, because it can be changed into another prime (114011540020171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005755010085 + 57005755010086.
It is an arithmetic number, because the mean of its divisors is an integer number (57005755010086).
Almost surely, 2114011510020171 is an apocalyptic number.
114011510020171 is a deficient number, since it is larger than the sum of its proper divisors (1).
114011510020171 is an equidigital number, since it uses as much as digits as its factorization.
114011510020171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 280, while the sum is 25.
Adding to 114011510020171 its reverse (171020015110411), we get a palindrome (285031525130582).
The spelling of 114011510020171 in words is "one hundred fourteen trillion, eleven billion, five hundred ten million, twenty thousand, one hundred seventy-one".
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