1140123311433 has 6 divisors (see below), whose sum is σ = 1646844783194. Its totient is φ = 760082207616.

The previous prime is 1140123311423. The next prime is 1140123311441. The reversal of 1140123311433 is 3341133210411.

1140123311433 is a `hidden beast` number, since 11 + 401 + 233 + 1 + 14 + 3 + 3 = 666.

It can be written as a sum of positive squares in only one way, i.e., 1139880793104 + 242518329 = 1067652^2 + 15573^2 .

It is not a de Polignac number, because 1140123311433 - 2³⁸ = 865245404489 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1140123311397 and 1140123311406.

It is not an unprimeable number, because it can be changed into a prime (1140123311423) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 63340183960 + ... + 63340183977.

Almost surely, 2^{1140123311433} is an apocalyptic number.

It is an amenable number.

1140123311433 is a deficient number, since it is larger than the sum of its proper divisors (506721471761).

1140123311433 is a wasteful number, since it uses less digits than its factorization.

1140123311433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 126680367943 (or 126680367940 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 1140123311433 its reverse (3341133210411), we get a palindrome (4481256521844).

The spelling of 1140123311433 in words is "one trillion, one hundred forty billion, one hundred twenty-three million, three hundred eleven thousand, four hundred thirty-three".