Base | Representation |
---|---|
bin | 11001111011000110010110… |
… | …011101100101111010111001 |
3 | 112221200111000100202111100112 |
4 | 121323012112131211322321 |
5 | 104420434424342242332 |
6 | 1042252330545514105 |
7 | 33005061221216126 |
oct | 3173062635457271 |
9 | 487614010674315 |
10 | 114012431212217 |
11 | 3336744513756a |
12 | 10954458642935 |
13 | 4b80431680965 |
14 | 202233426974d |
15 | d2aad1c19db2 |
hex | 67b196765eb9 |
114012431212217 has 2 divisors, whose sum is σ = 114012431212218. Its totient is φ = 114012431212216.
The previous prime is 114012431212151. The next prime is 114012431212243. The reversal of 114012431212217 is 712212134210411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113989018846096 + 23412366121 = 10676564^2 + 153011^2 .
It is a cyclic number.
It is not a de Polignac number, because 114012431212217 - 214 = 114012431195833 is a prime.
It is not a weakly prime, because it can be changed into another prime (114012431242217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006215606108 + 57006215606109.
It is an arithmetic number, because the mean of its divisors is an integer number (57006215606109).
Almost surely, 2114012431212217 is an apocalyptic number.
It is an amenable number.
114012431212217 is a deficient number, since it is larger than the sum of its proper divisors (1).
114012431212217 is an equidigital number, since it uses as much as digits as its factorization.
114012431212217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 32.
Adding to 114012431212217 its reverse (712212134210411), we get a palindrome (826224565422628).
The spelling of 114012431212217 in words is "one hundred fourteen trillion, twelve billion, four hundred thirty-one million, two hundred twelve thousand, two hundred seventeen".
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