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1140124433 = 7416915749
BaseRepresentation
bin100001111110100…
…1110101100010001
32221110100022200212
41003331032230101
54313332440213
6305044453505
740152616640
oct10375165421
92843308625
101140124433
115356303a8
122799aa295
1315228c056
14ab5c5357
156a15e9a8
hex43f4eb11

1140124433 has 16 divisors (see below), whose sum is σ = 1336944000. Its totient is φ = 951868800.

The previous prime is 1140124429. The next prime is 1140124441. The reversal of 1140124433 is 3344210411.

It is a cyclic number.

It is not a de Polignac number, because 1140124433 - 22 = 1140124429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1140124399 and 1140124408.

It is not an unprimeable number, because it can be changed into a prime (1140124493) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 195443 + ... + 201191.

It is an arithmetic number, because the mean of its divisors is an integer number (83559000).

Almost surely, 21140124433 is an apocalyptic number.

It is an amenable number.

1140124433 is a deficient number, since it is larger than the sum of its proper divisors (196819567).

1140124433 is an equidigital number, since it uses as much as digits as its factorization.

1140124433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6488.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 1140124433 is about 33765.7286756854. The cubic root of 1140124433 is about 1044.6819336786.

Adding to 1140124433 its reverse (3344210411), we get a palindrome (4484334844).

The spelling of 1140124433 in words is "one billion, one hundred forty million, one hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 7 41 287 691 4837 5749 28331 40243 198317 235709 1649963 3972559 27807913 162874919 1140124433