Base | Representation |
---|---|
bin | 11001111011000110011010… |
… | …101100000101110001011001 |
3 | 112221200111012022012001200112 |
4 | 121323012122230011301121 |
5 | 104420440101020342221 |
6 | 1042252342001414105 |
7 | 33005063042020661 |
oct | 3173063254056131 |
9 | 487614168161615 |
10 | 114012502121561 |
11 | 3336748116982a |
12 | 1095447833a335 |
13 | 4b8044327a354 |
14 | 202233d8471a1 |
15 | d2aad807515b |
hex | 67b19ab05c59 |
114012502121561 has 2 divisors, whose sum is σ = 114012502121562. Its totient is φ = 114012502121560.
The previous prime is 114012502121537. The next prime is 114012502121599. The reversal of 114012502121561 is 165121205210411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109383485326336 + 4629016795225 = 10458656^2 + 2151515^2 .
It is a cyclic number.
It is not a de Polignac number, because 114012502121561 - 210 = 114012502120537 is a prime.
It is not a weakly prime, because it can be changed into another prime (114012502111561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006251060780 + 57006251060781.
It is an arithmetic number, because the mean of its divisors is an integer number (57006251060781).
Almost surely, 2114012502121561 is an apocalyptic number.
It is an amenable number.
114012502121561 is a deficient number, since it is larger than the sum of its proper divisors (1).
114012502121561 is an equidigital number, since it uses as much as digits as its factorization.
114012502121561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 32.
Adding to 114012502121561 its reverse (165121205210411), we get a palindrome (279133707331972).
The spelling of 114012502121561 in words is "one hundred fourteen trillion, twelve billion, five hundred two million, one hundred twenty-one thousand, five hundred sixty-one".
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