114012535350547 has 2 divisors, whose sum is σ = 114012535350548. Its totient is φ = 114012535350546.

The previous prime is 114012535350457. The next prime is 114012535350589. The reversal of 114012535350547 is 745053535210411.

Together with previous prime (114012535350457) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114012535350547 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114012535350497 and 114012535350506.

It is not a weakly prime, because it can be changed into another prime (114012535357547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006267675273 + 57006267675274.

It is an arithmetic number, because the mean of its divisors is an integer number (57006267675274).

Almost surely, 2^{114012535350547} is an apocalyptic number.

114012535350547 is a deficient number, since it is larger than the sum of its proper divisors (1).

114012535350547 is an equidigital number, since it uses as much as digits as its factorization.

114012535350547 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260000, while the sum is 46.

The spelling of 114012535350547 in words is "one hundred fourteen trillion, twelve billion, five hundred thirty-five million, three hundred fifty thousand, five hundred forty-seven".