Base | Representation |
---|---|
bin | 11001111011000110011100… |
… | …101010110111011011101011 |
3 | 112221200111021121201111112220 |
4 | 121323012130222313123223 |
5 | 104420440133022330430 |
6 | 1042252345150005123 |
7 | 33005063624344545 |
oct | 3173063452673353 |
9 | 487614247644486 |
10 | 114012535355115 |
11 | 333674989a8681 |
12 | 109544874a67a3 |
13 | 4b8044a115087 |
14 | 2022344018695 |
15 | d2aadae3c110 |
hex | 67b19cab76eb |
114012535355115 has 16 divisors (see below), whose sum is σ = 183093193314816. Its totient is φ = 60582306607200.
The previous prime is 114012535355063. The next prime is 114012535355167. The reversal of 114012535355115 is 511553535210411.
It is an interprime number because it is at equal distance from previous prime (114012535355063) and next prime (114012535355167).
It is not a de Polignac number, because 114012535355115 - 213 = 114012535346923 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14023678021 + ... + 14023686150.
It is an arithmetic number, because the mean of its divisors is an integer number (11443324582176).
Almost surely, 2114012535355115 is an apocalyptic number.
114012535355115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114012535355115 is a deficient number, since it is larger than the sum of its proper divisors (69080657959701).
114012535355115 is a wasteful number, since it uses less digits than its factorization.
114012535355115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28047364450.
The product of its (nonzero) digits is 225000, while the sum is 42.
The spelling of 114012535355115 in words is "one hundred fourteen trillion, twelve billion, five hundred thirty-five million, three hundred fifty-five thousand, one hundred fifteen".
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