Base | Representation |
---|---|
bin | 11001111011000110011101… |
… | …000100001110110100101011 |
3 | 112221200111022002020022211021 |
4 | 121323012131010032310223 |
5 | 104420440141223121043 |
6 | 1042252345544313311 |
7 | 33005064035020561 |
oct | 3173063504166453 |
9 | 487614262208737 |
10 | 114012542004523 |
11 | 333674a172a458 |
12 | 10954489772837 |
13 | 4b8044b602836 |
14 | 2022344c69a31 |
15 | d2aadb8023ed |
hex | 67b19d10ed2b |
114012542004523 has 4 divisors (see below), whose sum is σ = 114021709223040. Its totient is φ = 114003374786008.
The previous prime is 114012542004509. The next prime is 114012542004533. The reversal of 114012542004523 is 325400245210411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114012542004523 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114012542004533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4583590603 + ... + 4583615476.
It is an arithmetic number, because the mean of its divisors is an integer number (28505427305760).
Almost surely, 2114012542004523 is an apocalyptic number.
114012542004523 is a deficient number, since it is larger than the sum of its proper divisors (9167218517).
114012542004523 is an equidigital number, since it uses as much as digits as its factorization.
114012542004523 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9167218516.
The product of its (nonzero) digits is 38400, while the sum is 34.
Adding to 114012542004523 its reverse (325400245210411), we get a palindrome (439412787214934).
The spelling of 114012542004523 in words is "one hundred fourteen trillion, twelve billion, five hundred forty-two million, four thousand, five hundred twenty-three".
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