Base | Representation |
---|---|
bin | 1010010111101001001010… |
… | …1111001101111100110011 |
3 | 1111100221202112220201020121 |
4 | 2211322102233031330303 |
5 | 2443244333043230102 |
6 | 40125404235351111 |
7 | 2254500652650436 |
oct | 245722257157463 |
9 | 44327675821217 |
10 | 11401305055027 |
11 | 36a62a2521488 |
12 | 1341795bb2497 |
13 | 6491a524a1b4 |
14 | 2b5b7cbb381d |
15 | 14b892940b37 |
hex | a5e92bcdf33 |
11401305055027 has 2 divisors, whose sum is σ = 11401305055028. Its totient is φ = 11401305055026.
The previous prime is 11401305054991. The next prime is 11401305055037. The reversal of 11401305055027 is 72055050310411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11401305055027 - 219 = 11401304530739 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11401305054983 and 11401305055001.
It is not a weakly prime, because it can be changed into another prime (11401305055037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700652527513 + 5700652527514.
It is an arithmetic number, because the mean of its divisors is an integer number (5700652527514).
Almost surely, 211401305055027 is an apocalyptic number.
11401305055027 is a deficient number, since it is larger than the sum of its proper divisors (1).
11401305055027 is an equidigital number, since it uses as much as digits as its factorization.
11401305055027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21000, while the sum is 34.
Adding to 11401305055027 its reverse (72055050310411), we get a palindrome (83456355365438).
The spelling of 11401305055027 in words is "eleven trillion, four hundred one billion, three hundred five million, fifty-five thousand, twenty-seven".
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