1140131241331 has 4 divisors (see below), whose sum is σ = 1151885171752. Its totient is φ = 1128377310912.

The previous prime is 1140131241329. The next prime is 1140131241343. The reversal of 1140131241331 is 1331421310411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1140131241331 - 2¹ = 1140131241329 is a prime.

It is a super-2 number, since 2×1140131241331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1140131241296 and 1140131241305.

It is not an unprimeable number, because it can be changed into a prime (1140131241311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5876965065 + ... + 5876965258.

It is an arithmetic number, because the mean of its divisors is an integer number (287971292938).

Almost surely, 2^{1140131241331} is an apocalyptic number.

1140131241331 is a deficient number, since it is larger than the sum of its proper divisors (11753930421).

1140131241331 is an equidigital number, since it uses as much as digits as its factorization.

1140131241331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11753930420.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1140131241331 its reverse (1331421310411), we get a palindrome (2471552551742).

The spelling of 1140131241331 in words is "one trillion, one hundred forty billion, one hundred thirty-one million, two hundred forty-one thousand, three hundred thirty-one".