114013403233 has 4 divisors (see below), whose sum is σ = 116794217988. Its totient is φ = 111232588480.

The previous prime is 114013403221. The next prime is 114013403261. The reversal of 114013403233 is 332304310411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 332304310411 = 337 ⋅986066203.

It can be written as a sum of positive squares in 2 ways, for example, as 25168870609 + 88844532624 = 158647^2 + 298068^2 .

It is a cyclic number.

It is not a de Polignac number, because 114013403233 - 2⁹ = 114013402721 is a prime.

It is a super-2 number, since 2×114013403233² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114013403198 and 114013403207.

It is not an unprimeable number, because it can be changed into a prime (114013403033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1390407316 + ... + 1390407397.

It is an arithmetic number, because the mean of its divisors is an integer number (29198554497).

Almost surely, 2^114013403233 is an apocalyptic number.

It is an amenable number.

114013403233 is a deficient number, since it is larger than the sum of its proper divisors (2780814755).

114013403233 is an equidigital number, since it uses as much as digits as its factorization.

114013403233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2780814754.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 114013403233 its reverse (332304310411), we get a palindrome (446317713644).

The spelling of 114013403233 in words is "one hundred fourteen billion, thirteen million, four hundred three thousand, two hundred thirty-three".