Base | Representation |
---|---|
bin | 110101000101110111… |
… | …0101001001011100011 |
3 | 101220021210100022220121 |
4 | 1222023232221023203 |
5 | 3331444413110034 |
6 | 124213235021111 |
7 | 11144233665205 |
oct | 1521356511343 |
9 | 356253308817 |
10 | 114013410019 |
11 | 443976634a3 |
12 | 1a11aa3a797 |
13 | a99cb35332 |
14 | 5738228775 |
15 | 2e7461b1b4 |
hex | 1a8bba92e3 |
114013410019 has 2 divisors, whose sum is σ = 114013410020. Its totient is φ = 114013410018.
The previous prime is 114013409977. The next prime is 114013410059. The reversal of 114013410019 is 910014310411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114013410019 - 211 = 114013407971 is a prime.
It is a super-2 number, since 2×1140134100192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114013409975 and 114013410002.
It is not a weakly prime, because it can be changed into another prime (114013410059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006705009 + 57006705010.
It is an arithmetic number, because the mean of its divisors is an integer number (57006705010).
Almost surely, 2114013410019 is an apocalyptic number.
114013410019 is a deficient number, since it is larger than the sum of its proper divisors (1).
114013410019 is an equidigital number, since it uses as much as digits as its factorization.
114013410019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 114013410019 in words is "one hundred fourteen billion, thirteen million, four hundred ten thousand, nineteen".
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