Base | Representation |
---|---|
bin | 10000100101110101010… |
… | …010111110101111111001 |
3 | 11000222212220201120110002 |
4 | 100211311102332233321 |
5 | 122134443331241241 |
6 | 2231434225402345 |
7 | 145241406111203 |
oct | 20456522765771 |
9 | 4028786646402 |
10 | 1140134243321 |
11 | 3aa58a06a027 |
12 | 164b707993b5 |
13 | 8368b900848 |
14 | 3d27b81b773 |
15 | 1e9ce15389b |
hex | 109754bebf9 |
1140134243321 has 2 divisors, whose sum is σ = 1140134243322. Its totient is φ = 1140134243320.
The previous prime is 1140134243317. The next prime is 1140134243351. The reversal of 1140134243321 is 1233424310411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 907848801721 + 232285441600 = 952811^2 + 481960^2 .
It is a cyclic number.
It is not a de Polignac number, because 1140134243321 - 22 = 1140134243317 is a prime.
It is not a weakly prime, because it can be changed into another prime (1140134243351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570067121660 + 570067121661.
It is an arithmetic number, because the mean of its divisors is an integer number (570067121661).
Almost surely, 21140134243321 is an apocalyptic number.
It is an amenable number.
1140134243321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140134243321 is an equidigital number, since it uses as much as digits as its factorization.
1140134243321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1140134243321 its reverse (1233424310411), we get a palindrome (2373558553732).
The spelling of 1140134243321 in words is "one trillion, one hundred forty billion, one hundred thirty-four million, two hundred forty-three thousand, three hundred twenty-one".
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