114013500321433 has 2 divisors, whose sum is σ = 114013500321434. Its totient is φ = 114013500321432.

The previous prime is 114013500321379. The next prime is 114013500321493. The reversal of 114013500321433 is 334123005310411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110636149530384 + 3377350791049 = 10518372^2 + 1837757^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114013500321433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114013500321395 and 114013500321404.

It is not a weakly prime, because it can be changed into another prime (114013500321493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006750160716 + 57006750160717.

It is an arithmetic number, because the mean of its divisors is an integer number (57006750160717).

Almost surely, 2^{114013500321433} is an apocalyptic number.

It is an amenable number.

114013500321433 is a deficient number, since it is larger than the sum of its proper divisors (1).

114013500321433 is an equidigital number, since it uses as much as digits as its factorization.

114013500321433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 114013500321433 its reverse (334123005310411), we get a palindrome (448136505631844).

The spelling of 114013500321433 in words is "one hundred fourteen trillion, thirteen billion, five hundred million, three hundred twenty-one thousand, four hundred thirty-three".