Base | Representation |
---|---|
bin | 10101001111001111… |
… | …00111010001010011 |
3 | 1002102122002102010101 |
4 | 22213213213101103 |
5 | 141322420123011 |
6 | 5123230513231 |
7 | 552361241152 |
oct | 124747472123 |
9 | 32378072111 |
10 | 11402114131 |
11 | 4921218121 |
12 | 2262665817 |
13 | 10c93292c5 |
14 | 7a2465599 |
15 | 46b01e2c1 |
hex | 2a79e7453 |
11402114131 has 4 divisors (see below), whose sum is σ = 11644712352. Its totient is φ = 11159515912.
The previous prime is 11402114107. The next prime is 11402114173. The reversal of 11402114131 is 13141120411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11402114131 - 229 = 10865243219 is a prime.
It is a super-2 number, since 2×114021141312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11402114099 and 11402114108.
It is not an unprimeable number, because it can be changed into a prime (11402114831) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121299040 + ... + 121299133.
It is an arithmetic number, because the mean of its divisors is an integer number (2911178088).
Almost surely, 211402114131 is an apocalyptic number.
11402114131 is a deficient number, since it is larger than the sum of its proper divisors (242598221).
11402114131 is an equidigital number, since it uses as much as digits as its factorization.
11402114131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 242598220.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 11402114131 its reverse (13141120411), we get a palindrome (24543234542).
The spelling of 11402114131 in words is "eleven billion, four hundred two million, one hundred fourteen thousand, one hundred thirty-one".
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