Base | Representation |
---|---|
bin | 110101000110000111… |
… | …1111111000110000011 |
3 | 101220022101210101122021 |
4 | 1222030033333012003 |
5 | 3332004132304111 |
6 | 124214150222311 |
7 | 11144401200562 |
oct | 1521417770603 |
9 | 356271711567 |
10 | 114022150531 |
11 | 443a1593363 |
12 | 1a121954997 |
13 | a9a18a5833 |
14 | 5739461bd9 |
15 | 2e75295d71 |
hex | 1a8c3ff183 |
114022150531 has 4 divisors (see below), whose sum is σ = 114024835600. Its totient is φ = 114019465464.
The previous prime is 114022150507. The next prime is 114022150537. The reversal of 114022150531 is 135051220411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114022150531 - 29 = 114022150019 is a prime.
It is a super-2 number, since 2×1140221505312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114022150496 and 114022150505.
It is not an unprimeable number, because it can be changed into a prime (114022150537) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1277796 + ... + 1364113.
It is an arithmetic number, because the mean of its divisors is an integer number (28506208900).
Almost surely, 2114022150531 is an apocalyptic number.
114022150531 is a deficient number, since it is larger than the sum of its proper divisors (2685069).
114022150531 is an equidigital number, since it uses as much as digits as its factorization.
114022150531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2685068.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 114022150531 its reverse (135051220411), we get a palindrome (249073370942).
The spelling of 114022150531 in words is "one hundred fourteen billion, twenty-two million, one hundred fifty thousand, five hundred thirty-one".
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