11402301331 has 2 divisors, whose sum is σ = 11402301332. Its totient is φ = 11402301330.

The previous prime is 11402301307. The next prime is 11402301343. The reversal of 11402301331 is 13310320411.

It is a strong prime.

It is an emirp because it is prime and its reverse (13310320411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11402301331 - 2²⁵ = 11368746899 is a prime.

It is a super-2 number, since 2×11402301331² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11402301299 and 11402301308.

It is not a weakly prime, because it can be changed into another prime (11402301371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701150665 + 5701150666.

It is an arithmetic number, because the mean of its divisors is an integer number (5701150666).

Almost surely, 2^11402301331 is an apocalyptic number.

11402301331 is a deficient number, since it is larger than the sum of its proper divisors (1).

11402301331 is an equidigital number, since it uses as much as digits as its factorization.

11402301331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11402301331 its reverse (13310320411), we get a palindrome (24712621742).

The spelling of 11402301331 in words is "eleven billion, four hundred two million, three hundred one thousand, three hundred thirty-one".