Base | Representation |
---|---|
bin | 10101001111010000… |
… | …11110011101111001 |
3 | 1002102122111220020221 |
4 | 22213220132131321 |
5 | 141322444341332 |
6 | 5123235420041 |
7 | 552363202252 |
oct | 124750363571 |
9 | 32378456227 |
10 | 11402340217 |
11 | 4921361a74 |
12 | 2262754621 |
13 | 10c93a8198 |
14 | 7a24c3b29 |
15 | 46b066297 |
hex | 2a7a1e779 |
11402340217 has 2 divisors, whose sum is σ = 11402340218. Its totient is φ = 11402340216.
The previous prime is 11402340199. The next prime is 11402340223. The reversal of 11402340217 is 71204320411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10704799296 + 697540921 = 103464^2 + 26411^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11402340217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11402340191 and 11402340200.
It is not a weakly prime, because it can be changed into another prime (11402340227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701170108 + 5701170109.
It is an arithmetic number, because the mean of its divisors is an integer number (5701170109).
Almost surely, 211402340217 is an apocalyptic number.
It is an amenable number.
11402340217 is a deficient number, since it is larger than the sum of its proper divisors (1).
11402340217 is an equidigital number, since it uses as much as digits as its factorization.
11402340217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 11402340217 its reverse (71204320411), we get a palindrome (82606660628).
The spelling of 11402340217 in words is "eleven billion, four hundred two million, three hundred forty thousand, two hundred seventeen".
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