Base | Representation |
---|---|
bin | 10000100101111011001… |
… | …111111100010001000001 |
3 | 11001000010212122022210121 |
4 | 100211323033330101001 |
5 | 122140144413010032 |
6 | 2231452154100241 |
7 | 145244031006562 |
oct | 20457317742101 |
9 | 4030125568717 |
10 | 1140234110017 |
11 | 3aa63047a392 |
12 | 164b9a11a681 |
13 | 836a64c8772 |
14 | 3d28abb6169 |
15 | 1e9d7ccda97 |
hex | 1097b3fc441 |
1140234110017 has 2 divisors, whose sum is σ = 1140234110018. Its totient is φ = 1140234110016.
The previous prime is 1140234109979. The next prime is 1140234110069. The reversal of 1140234110017 is 7100114320411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1138508206081 + 1725903936 = 1067009^2 + 41544^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1140234110017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1140234109973 and 1140234110000.
It is not a weakly prime, because it can be changed into another prime (1140234116017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570117055008 + 570117055009.
It is an arithmetic number, because the mean of its divisors is an integer number (570117055009).
Almost surely, 21140234110017 is an apocalyptic number.
It is an amenable number.
1140234110017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140234110017 is an equidigital number, since it uses as much as digits as its factorization.
1140234110017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 1140234110017 its reverse (7100114320411), we get a palindrome (8240348430428).
The spelling of 1140234110017 in words is "one trillion, one hundred forty billion, two hundred thirty-four million, one hundred ten thousand, seventeen".
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