1140234141433 has 4 divisors (see below), whose sum is σ = 1140236580340. Its totient is φ = 1140231702528.

The previous prime is 1140234141421. The next prime is 1140234141437. The reversal of 1140234141433 is 3341414320411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 694693911289 + 445540230144 = 833483^2 + 667488^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1140234141433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1140234141395 and 1140234141404.

It is not an unprimeable number, because it can be changed into a prime (1140234141437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 273660 + ... + 1534717.

It is an arithmetic number, because the mean of its divisors is an integer number (285059145085).

Almost surely, 2^{1140234141433} is an apocalyptic number.

It is an amenable number.

1140234141433 is a deficient number, since it is larger than the sum of its proper divisors (2438907).

1140234141433 is an equidigital number, since it uses as much as digits as its factorization.

1140234141433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2438906.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1140234141433 its reverse (3341414320411), we get a palindrome (4481648461844).

The spelling of 1140234141433 in words is "one trillion, one hundred forty billion, two hundred thirty-four million, one hundred forty-one thousand, four hundred thirty-three".