114030013003 has 4 divisors (see below), whose sum is σ = 114031094688. Its totient is φ = 114028931320.

The previous prime is 114030013001. The next prime is 114030013007. The reversal of 114030013003 is 300310030411.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 300310030411 = 3413 ⋅87990047.

It is a cyclic number.

It is not a de Polignac number, because 114030013003 - 2¹ = 114030013001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114030013001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 363283 + ... + 600028.

It is an arithmetic number, because the mean of its divisors is an integer number (28507773672).

Almost surely, 2^114030013003 is an apocalyptic number.

114030013003 is a deficient number, since it is larger than the sum of its proper divisors (1081685).

114030013003 is an equidigital number, since it uses as much as digits as its factorization.

114030013003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1081684.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 114030013003 its reverse (300310030411), we get a palindrome (414340043414).

The spelling of 114030013003 in words is "one hundred fourteen billion, thirty million, thirteen thousand, three".