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114030435301411 = 196001601857969
BaseRepresentation
bin11001111011010111000111…
…100101101111100000100011
3112221202012111002121222200211
4121323113013211233200203
5104421233312414121121
61042304505255554551
733006266326362106
oct3173270745574043
9487665432558624
10114030435301411
1133374043a62222
1210957a4208ba57
134b820406b3585
14202316143c73d
15d2b2d762ece1
hex67b5c796f823

114030435301411 has 4 divisors (see below), whose sum is σ = 120032037159400. Its totient is φ = 108028833443424.

The previous prime is 114030435301339. The next prime is 114030435301417. The reversal of 114030435301411 is 114103534030411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114030435301411 - 243 = 105234342279203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114030435301417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3000800928966 + ... + 3000800929003.

It is an arithmetic number, because the mean of its divisors is an integer number (30008009289850).

Almost surely, 2114030435301411 is an apocalyptic number.

114030435301411 is a deficient number, since it is larger than the sum of its proper divisors (6001601857989).

114030435301411 is an equidigital number, since it uses as much as digits as its factorization.

114030435301411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6001601857988.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 114030435301411 its reverse (114103534030411), we get a palindrome (228133969331822).

The spelling of 114030435301411 in words is "one hundred fourteen trillion, thirty billion, four hundred thirty-five million, three hundred one thousand, four hundred eleven".

Divisors: 1 19 6001601857969 114030435301411