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11403044057163 = 311594715810341
BaseRepresentation
bin1010010111101111101001…
…1000111111000001001011
31111101010020202011011201010
42211323322120333001023
52443311413234312123
640130253000255003
72254562030143503
oct245737230770113
944333222134633
1011403044057163
1136a7005103530
121341ba0471463
136493c1601045
142b5ca5b2ca03
1514b94544a993
hexa5efa63f04b

11403044057163 has 16 divisors (see below), whose sum is σ = 16586527652352. Its totient is φ = 6910818396000.

The previous prime is 11403044057113. The next prime is 11403044057189. The reversal of 11403044057163 is 36175044030411.

It is not a de Polignac number, because 11403044057163 - 214 = 11403044040779 is a prime.

It is a super-2 number, since 2×114030440571632 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11403044057113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 942628 + ... + 4867713.

It is an arithmetic number, because the mean of its divisors is an integer number (1036657978272).

Almost surely, 211403044057163 is an apocalyptic number.

11403044057163 is a deficient number, since it is larger than the sum of its proper divisors (5183483595189).

11403044057163 is a wasteful number, since it uses less digits than its factorization.

11403044057163 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5869826.

The product of its (nonzero) digits is 120960, while the sum is 39.

Adding to 11403044057163 its reverse (36175044030411), we get a palindrome (47578088087574).

The spelling of 11403044057163 in words is "eleven trillion, four hundred three billion, forty-four million, fifty-seven thousand, one hundred sixty-three".

Divisors: 1 3 11 33 59471 178413 654181 1962543 5810341 17431023 63913751 191741253 345546789611 1036640368833 3801014685721 11403044057163