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114031110322 = 257015555161
BaseRepresentation
bin110101000110011001…
…0001010100010110010
3101220100000122121011101
41222030302022202302
53332013431012242
6124215110235014
711144540305453
oct1521462124262
9356300577141
10114031110322
11443a6652a48
121a124955a6a
13a9a36c1a9c
14573a71512a
152e75e659b7
hex1a8cc8a8b2

114031110322 has 4 divisors (see below), whose sum is σ = 171046665486. Its totient is φ = 57015555160.

The previous prime is 114031110287. The next prime is 114031110373. The reversal of 114031110322 is 223011130411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 223011130411 = 564139533971.

It can be written as a sum of positive squares in only one way, i.e., 93274657281 + 20756453041 = 305409^2 + 144071^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 114031110322.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28507777579 + ... + 28507777582.

Almost surely, 2114031110322 is an apocalyptic number.

114031110322 is a deficient number, since it is larger than the sum of its proper divisors (57015555164).

114031110322 is an equidigital number, since it uses as much as digits as its factorization.

114031110322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57015555163.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 114031110322 its reverse (223011130411), we get a palindrome (337042240733).

The spelling of 114031110322 in words is "one hundred fourteen billion, thirty-one million, one hundred ten thousand, three hundred twenty-two".

Divisors: 1 2 57015555161 114031110322