Base | Representation |
---|---|
bin | 10101001111010110… |
… | …11110001011000001 |
3 | 1002102200222210101022 |
4 | 22213223132023001 |
5 | 141323200003231 |
6 | 5123304315225 |
7 | 552402652451 |
oct | 124753361301 |
9 | 32380883338 |
10 | 11403125441 |
11 | 4921848a14 |
12 | 2262a72b15 |
13 | 10c95c1706 |
14 | 7a2649d61 |
15 | 46b16dc7b |
hex | 2a7ade2c1 |
11403125441 has 2 divisors, whose sum is σ = 11403125442. Its totient is φ = 11403125440.
The previous prime is 11403125431. The next prime is 11403125537. The reversal of 11403125441 is 14452130411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9624394816 + 1778730625 = 98104^2 + 42175^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11403125441 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11403125441.
It is not a weakly prime, because it can be changed into another prime (11403125401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701562720 + 5701562721.
It is an arithmetic number, because the mean of its divisors is an integer number (5701562721).
Almost surely, 211403125441 is an apocalyptic number.
It is an amenable number.
11403125441 is a deficient number, since it is larger than the sum of its proper divisors (1).
11403125441 is an equidigital number, since it uses as much as digits as its factorization.
11403125441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1920, while the sum is 26.
Adding to 11403125441 its reverse (14452130411), we get a palindrome (25855255852).
The spelling of 11403125441 in words is "eleven billion, four hundred three million, one hundred twenty-five thousand, four hundred forty-one".
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