11403130034 has 4 divisors (see below), whose sum is σ = 17104695054. Its totient is φ = 5701565016.

The previous prime is 11403130021. The next prime is 11403130061. The reversal of 11403130034 is 43003130411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43003130411 = 61 ⋅704969351.

It can be written as a sum of positive squares in only one way, i.e., 7458913225 + 3944216809 = 86365^2 + 62803^2 .

It is a super-3 number, since 3×11403130034³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11403129988 and 11403130015.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2850782507 + ... + 2850782510.

Almost surely, 2^11403130034 is an apocalyptic number.

11403130034 is a deficient number, since it is larger than the sum of its proper divisors (5701565020).

11403130034 is an equidigital number, since it uses as much as digits as its factorization.

11403130034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5701565019.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 11403130034 its reverse (43003130411), we get a palindrome (54406260445).

The spelling of 11403130034 in words is "eleven billion, four hundred three million, one hundred thirty thousand, thirty-four".