1140313034131 has 4 divisors (see below), whose sum is σ = 1143185359552. Its totient is φ = 1137440708712.

The previous prime is 1140313034123. The next prime is 1140313034143. The reversal of 1140313034131 is 1314303130411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1140313034131 - 2³ = 1140313034123 is a prime.

It is a super-2 number, since 2×1140313034131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1140313034096 and 1140313034105.

It is not an unprimeable number, because it can be changed into a prime (1140313034171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1436162115 + ... + 1436162908.

It is an arithmetic number, because the mean of its divisors is an integer number (285796339888).

Almost surely, 2^{1140313034131} is an apocalyptic number.

1140313034131 is a deficient number, since it is larger than the sum of its proper divisors (2872325421).

1140313034131 is an equidigital number, since it uses as much as digits as its factorization.

1140313034131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2872325420.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1140313034131 its reverse (1314303130411), we get a palindrome (2454616164542).

The spelling of 1140313034131 in words is "one trillion, one hundred forty billion, three hundred thirteen million, thirty-four thousand, one hundred thirty-one".