Search a number
-
+
1140313131313 is a prime number
BaseRepresentation
bin10000100101111111111…
…101011000100100110001
311001000100101100000122021
4100211333331120210301
5122140330130200223
62231504055511441
7145246010455426
oct20457775304461
94030311300567
101140313131313
113aa671042244
12165000688581
13836b99a5525
143d2974a5d4d
151e9debdc65d
hex1097ff58931

1140313131313 has 2 divisors, whose sum is σ = 1140313131314. Its totient is φ = 1140313131312.

The previous prime is 1140313131283. The next prime is 1140313131317. The reversal of 1140313131313 is 3131313130411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 671077171249 + 469235960064 = 819193^2 + 685008^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1140313131313 is a prime.

It is a super-2 number, since 2×11403131313132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1140313131317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570156565656 + 570156565657.

It is an arithmetic number, because the mean of its divisors is an integer number (570156565657).

Almost surely, 21140313131313 is an apocalyptic number.

It is an amenable number.

1140313131313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140313131313 is an equidigital number, since it uses as much as digits as its factorization.

1140313131313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 1140313131313 its reverse (3131313130411), we get a palindrome (4271626261724).

The spelling of 1140313131313 in words is "one trillion, one hundred forty billion, three hundred thirteen million, one hundred thirty-one thousand, three hundred thirteen".