Base | Representation |
---|---|
bin | 110101000110011001… |
… | …1010110111001101001 |
3 | 101220100001020111012001 |
4 | 1222030303112321221 |
5 | 3332014021014311 |
6 | 124215121051001 |
7 | 11144543050342 |
oct | 1521463267151 |
9 | 356301214161 |
10 | 114031423081 |
11 | 443a6846a24 |
12 | 1a124a86a61 |
13 | a9a37a1254 |
14 | 573a7970c9 |
15 | 2e75ec84c1 |
hex | 1a8ccd6e69 |
114031423081 has 2 divisors, whose sum is σ = 114031423082. Its totient is φ = 114031423080.
The previous prime is 114031423069. The next prime is 114031423159. The reversal of 114031423081 is 180324130411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109092144681 + 4939278400 = 330291^2 + 70280^2 .
It is a cyclic number.
It is not a de Polignac number, because 114031423081 - 25 = 114031423049 is a prime.
It is a super-2 number, since 2×1140314230812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114031423021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57015711540 + 57015711541.
It is an arithmetic number, because the mean of its divisors is an integer number (57015711541).
Almost surely, 2114031423081 is an apocalyptic number.
It is an amenable number.
114031423081 is a deficient number, since it is larger than the sum of its proper divisors (1).
114031423081 is an equidigital number, since it uses as much as digits as its factorization.
114031423081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 114031423081 its reverse (180324130411), we get a palindrome (294355553492).
The spelling of 114031423081 in words is "one hundred fourteen billion, thirty-one million, four hundred twenty-three thousand, eighty-one".
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