114032015555243 has 4 divisors (see below), whose sum is σ = 114260536629000. Its totient is φ = 113803494481488.

The previous prime is 114032015555233. The next prime is 114032015555251. The reversal of 114032015555243 is 342555510230411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114032015555243 - 2¹² = 114032015551147 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 114032015555243.

It is not an unprimeable number, because it can be changed into a prime (114032015555203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114260536130 + ... + 114260537127.

It is an arithmetic number, because the mean of its divisors is an integer number (28565134157250).

Almost surely, 2^{114032015555243} is an apocalyptic number.

114032015555243 is a deficient number, since it is larger than the sum of its proper divisors (228521073757).

114032015555243 is an equidigital number, since it uses as much as digits as its factorization.

114032015555243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 228521073756.

The product of its (nonzero) digits is 360000, while the sum is 41.

Adding to 114032015555243 its reverse (342555510230411), we get a palindrome (456587525785654).

The spelling of 114032015555243 in words is "one hundred fourteen trillion, thirty-two billion, fifteen million, five hundred fifty-five thousand, two hundred forty-three".