Base | Representation |
---|---|
bin | 10000100110000000111… |
… | …110100010100010000001 |
3 | 11001000101120110210012012 |
4 | 100212000332202202001 |
5 | 122140344013231312 |
6 | 2231505505542305 |
7 | 145246305603653 |
oct | 20460076424201 |
9 | 4030346423165 |
10 | 1140330211457 |
11 | 3aa67a748868 |
12 | 165006344995 |
13 | 836c03a5918 |
14 | 3d2998706d3 |
15 | 1e9e1463322 |
hex | 10980fa2881 |
1140330211457 has 2 divisors, whose sum is σ = 1140330211458. Its totient is φ = 1140330211456.
The previous prime is 1140330211429. The next prime is 1140330211483. The reversal of 1140330211457 is 7541120330411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1071558295921 + 68771915536 = 1035161^2 + 262244^2 .
It is a cyclic number.
It is not a de Polignac number, because 1140330211457 - 220 = 1140329162881 is a prime.
It is not a weakly prime, because it can be changed into another prime (1140330211487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570165105728 + 570165105729.
It is an arithmetic number, because the mean of its divisors is an integer number (570165105729).
Almost surely, 21140330211457 is an apocalyptic number.
It is an amenable number.
1140330211457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140330211457 is an equidigital number, since it uses as much as digits as its factorization.
1140330211457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 1140330211457 its reverse (7541120330411), we get a palindrome (8681450541868).
The spelling of 1140330211457 in words is "one trillion, one hundred forty billion, three hundred thirty million, two hundred eleven thousand, four hundred fifty-seven".
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