Base | Representation |
---|---|
bin | 110101000110011100… |
… | …1100000010011000001 |
3 | 101220100011021100112202 |
4 | 1222030321200103001 |
5 | 3332014424100213 |
6 | 124215215402545 |
7 | 11144562541223 |
oct | 1521471402301 |
9 | 356304240482 |
10 | 114033034433 |
11 | 443a774761a |
12 | 1a125523455 |
13 | a9a3c16806 |
14 | 573aa96413 |
15 | 2e761e5b58 |
hex | 1a8ce604c1 |
114033034433 has 2 divisors, whose sum is σ = 114033034434. Its totient is φ = 114033034432.
The previous prime is 114033034399. The next prime is 114033034553. The reversal of 114033034433 is 334430330411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 93508747264 + 20524287169 = 305792^2 + 143263^2 .
It is a cyclic number.
It is not a de Polignac number, because 114033034433 - 216 = 114032968897 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114033034396 and 114033034405.
It is not a weakly prime, because it can be changed into another prime (114033036433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57016517216 + 57016517217.
It is an arithmetic number, because the mean of its divisors is an integer number (57016517217).
Almost surely, 2114033034433 is an apocalyptic number.
It is an amenable number.
114033034433 is a deficient number, since it is larger than the sum of its proper divisors (1).
114033034433 is an equidigital number, since it uses as much as digits as its factorization.
114033034433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 114033034433 its reverse (334430330411), we get a palindrome (448463364844).
The spelling of 114033034433 in words is "one hundred fourteen billion, thirty-three million, thirty-four thousand, four hundred thirty-three".
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