Base | Representation |
---|---|
bin | 11001111011011010111010… |
… | …000010111010101010011111 |
3 | 112221202120222120210021220211 |
4 | 121323122322002322222133 |
5 | 104421320130234114201 |
6 | 1042310421045353251 |
7 | 33006502201504240 |
oct | 3173327202725237 |
9 | 487676876707824 |
10 | 114034503035551 |
11 | 333758410aa07a |
12 | 10958798408827 |
13 | 4b8253b35c357 |
14 | 2023429784cc7 |
15 | d2b4747d4651 |
hex | 67b6ba0baa9f |
114034503035551 has 32 divisors (see below), whose sum is σ = 134789262336000. Its totient is φ = 94448740044672.
The previous prime is 114034503035543. The next prime is 114034503035561. The reversal of 114034503035551 is 155530305430411.
It is a cyclic number.
It is not a de Polignac number, because 114034503035551 - 23 = 114034503035543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114034503035561) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 610929105 + ... + 611115733.
It is an arithmetic number, because the mean of its divisors is an integer number (4212164448000).
Almost surely, 2114034503035551 is an apocalyptic number.
114034503035551 is a deficient number, since it is larger than the sum of its proper divisors (20754759300449).
114034503035551 is a wasteful number, since it uses less digits than its factorization.
114034503035551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 210271.
The product of its (nonzero) digits is 270000, while the sum is 40.
Adding to 114034503035551 its reverse (155530305430411), we get a palindrome (269564808465962).
The spelling of 114034503035551 in words is "one hundred fourteen trillion, thirty-four billion, five hundred three million, thirty-five thousand, five hundred fifty-one".
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