Base | Representation |
---|---|
bin | 1010010111110011101011… |
… | …0101001110001110010011 |
3 | 1111101020001002111222122112 |
4 | 2211330322311032032103 |
5 | 2443321122022420144 |
6 | 40130552141055535 |
7 | 2254630565544305 |
oct | 245747265161623 |
9 | 44336032458575 |
10 | 11404125201299 |
11 | 36a750a40a086 |
12 | 13422425575ab |
13 | 6495345ac2bc |
14 | 2b5d6955d975 |
15 | 14b9aa30999e |
hex | a5f3ad4e393 |
11404125201299 has 2 divisors, whose sum is σ = 11404125201300. Its totient is φ = 11404125201298.
The previous prime is 11404125201289. The next prime is 11404125201331. The reversal of 11404125201299 is 99210252140411.
It is a weak prime.
It is an emirp because it is prime and its reverse (99210252140411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11404125201299 - 212 = 11404125197203 is a prime.
It is not a weakly prime, because it can be changed into another prime (11404125201289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5702062600649 + 5702062600650.
It is an arithmetic number, because the mean of its divisors is an integer number (5702062600650).
Almost surely, 211404125201299 is an apocalyptic number.
11404125201299 is a deficient number, since it is larger than the sum of its proper divisors (1).
11404125201299 is an equidigital number, since it uses as much as digits as its factorization.
11404125201299 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 41.
The spelling of 11404125201299 in words is "eleven trillion, four hundred four billion, one hundred twenty-five million, two hundred one thousand, two hundred ninety-nine".
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