Base | Representation |
---|---|
bin | 10000100110000101111… |
… | …011010001100000111011 |
3 | 11001000121100201010212101 |
4 | 100212011323101200323 |
5 | 122141031242211103 |
6 | 2231522033324231 |
7 | 145251334416532 |
oct | 20460573214073 |
9 | 4030540633771 |
10 | 1140413241403 |
11 | 3aa7125a9457 |
12 | 16502a106677 |
13 | 83704657177 |
14 | 3d2a68c5319 |
15 | 1e9e88b4a1d |
hex | 10985ed183b |
1140413241403 has 2 divisors, whose sum is σ = 1140413241404. Its totient is φ = 1140413241402.
The previous prime is 1140413241367. The next prime is 1140413241419. The reversal of 1140413241403 is 3041423140411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1140413241403 - 229 = 1139876370491 is a prime.
It is a super-2 number, since 2×11404132414032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1140413245403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570206620701 + 570206620702.
It is an arithmetic number, because the mean of its divisors is an integer number (570206620702).
Almost surely, 21140413241403 is an apocalyptic number.
1140413241403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140413241403 is an equidigital number, since it uses as much as digits as its factorization.
1140413241403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1140413241403 its reverse (3041423140411), we get a palindrome (4181836381814).
The spelling of 1140413241403 in words is "one trillion, one hundred forty billion, four hundred thirteen million, two hundred forty-one thousand, four hundred three".
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