Base | Representation |
---|---|
bin | 110101000110110000… |
… | …1000101000000110001 |
3 | 101220100212210101222222 |
4 | 1222031201011000301 |
5 | 3332030103032213 |
6 | 124220230010425 |
7 | 11145046656143 |
oct | 1521541050061 |
9 | 356325711888 |
10 | 114043408433 |
11 | 44402592779 |
12 | 1a128aa6a15 |
13 | a9a6109686 |
14 | 573c1d6c93 |
15 | 2e77094808 |
hex | 1a8d845031 |
114043408433 has 2 divisors, whose sum is σ = 114043408434. Its totient is φ = 114043408432.
The previous prime is 114043408421. The next prime is 114043408441. The reversal of 114043408433 is 334804340411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 91295831104 + 22747577329 = 302152^2 + 150823^2 .
It is an emirp because it is prime and its reverse (334804340411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114043408433 - 28 = 114043408177 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114043408393 and 114043408402.
It is not a weakly prime, because it can be changed into another prime (114043408733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57021704216 + 57021704217.
It is an arithmetic number, because the mean of its divisors is an integer number (57021704217).
Almost surely, 2114043408433 is an apocalyptic number.
It is an amenable number.
114043408433 is a deficient number, since it is larger than the sum of its proper divisors (1).
114043408433 is an equidigital number, since it uses as much as digits as its factorization.
114043408433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 114043408433 its reverse (334804340411), we get a palindrome (448847748844).
The spelling of 114043408433 in words is "one hundred fourteen billion, forty-three million, four hundred eight thousand, four hundred thirty-three".
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