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114043408433 is a prime number
BaseRepresentation
bin110101000110110000…
…1000101000000110001
3101220100212210101222222
41222031201011000301
53332030103032213
6124220230010425
711145046656143
oct1521541050061
9356325711888
10114043408433
1144402592779
121a128aa6a15
13a9a6109686
14573c1d6c93
152e77094808
hex1a8d845031

114043408433 has 2 divisors, whose sum is σ = 114043408434. Its totient is φ = 114043408432.

The previous prime is 114043408421. The next prime is 114043408441. The reversal of 114043408433 is 334804340411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91295831104 + 22747577329 = 302152^2 + 150823^2 .

It is an emirp because it is prime and its reverse (334804340411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114043408433 - 28 = 114043408177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114043408393 and 114043408402.

It is not a weakly prime, because it can be changed into another prime (114043408733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57021704216 + 57021704217.

It is an arithmetic number, because the mean of its divisors is an integer number (57021704217).

Almost surely, 2114043408433 is an apocalyptic number.

It is an amenable number.

114043408433 is a deficient number, since it is larger than the sum of its proper divisors (1).

114043408433 is an equidigital number, since it uses as much as digits as its factorization.

114043408433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 114043408433 its reverse (334804340411), we get a palindrome (448847748844).

The spelling of 114043408433 in words is "one hundred fourteen billion, forty-three million, four hundred eight thousand, four hundred thirty-three".