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114044040001 = 367310746703
BaseRepresentation
bin110101000110110001…
…1011111001101000001
3101220100220222111100101
41222031203133031001
53332030233240001
6124220251322401
711145055226353
oct1521543371501
9356326874311
10114044040001
1144402984231
121a129150401
13a9a629ac98
14573c31d0d3
152e7716ba01
hex1a8d8df341

114044040001 has 4 divisors (see below), whose sum is σ = 114354787072. Its totient is φ = 113733292932.

The previous prime is 114044039959. The next prime is 114044040013. The reversal of 114044040001 is 100040440411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114044040001 - 29 = 114044039489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114044040601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155372985 + ... + 155373718.

It is an arithmetic number, because the mean of its divisors is an integer number (28588696768).

Almost surely, 2114044040001 is an apocalyptic number.

It is an amenable number.

114044040001 is a deficient number, since it is larger than the sum of its proper divisors (310747071).

114044040001 is an equidigital number, since it uses as much as digits as its factorization.

114044040001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 310747070.

The product of its (nonzero) digits is 256, while the sum is 19.

Adding to 114044040001 its reverse (100040440411), we get a palindrome (214084480412).

The spelling of 114044040001 in words is "one hundred fourteen billion, forty-four million, forty thousand, one".

Divisors: 1 367 310746703 114044040001